Termination of the given ITRSProblem could not be shown:



↳ ITRS
  ↳ ITRStoQTRSProof

ITRS problem:
The following domains are used:

z

The TRS R consists of the following rules:

f91(n) → cond(<=@z(n, 100@z), n)
cond(TRUE, n) → f91(f91(+@z(n, 11@z)))
cond(FALSE, n) → -@z(n, 10@z)

The set Q consists of the following terms:

f91(x0)
cond(TRUE, x0)
cond(FALSE, x0)


Represented integers and predefined function symbols by Terms

↳ ITRS
  ↳ ITRStoQTRSProof
    ↳ QTRS
      ↳ DependencyPairsProof

Q restricted rewrite system:
The TRS R consists of the following rules:

f91(n) → cond(lesseq_int(n, pos(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))), n)
cond(true, n) → f91(f91(plus_int(pos(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))), n)))
cond(false, n) → minus_int(n, pos(s(s(s(s(s(s(s(s(s(s(0))))))))))))
lesseq_int(pos(0), pos(y)) → true
lesseq_int(pos(0), neg(0)) → true
lesseq_int(neg(x), pos(y)) → true
lesseq_int(neg(x), neg(0)) → true
lesseq_int(pos(x), neg(s(y))) → false
lesseq_int(neg(0), neg(s(y))) → false
lesseq_int(pos(s(x)), pos(0)) → false
lesseq_int(pos(s(x)), neg(y)) → false
lesseq_int(pos(s(x)), pos(s(y))) → lesseq_int(pos(x), pos(y))
lesseq_int(neg(s(x)), neg(s(y))) → lesseq_int(neg(x), neg(y))
plus_int(pos(x), neg(y)) → minus_nat(x, y)
plus_int(neg(x), pos(y)) → minus_nat(y, x)
plus_int(neg(x), neg(y)) → neg(plus_nat(x, y))
plus_int(pos(x), pos(y)) → pos(plus_nat(x, y))
plus_nat(0, x) → x
plus_nat(s(x), y) → s(plus_nat(x, y))
minus_nat(0, 0) → pos(0)
minus_nat(0, s(y)) → neg(s(y))
minus_nat(s(x), 0) → pos(s(x))
minus_nat(s(x), s(y)) → minus_nat(x, y)
minus_int(pos(x), pos(y)) → minus_nat(x, y)
minus_int(neg(x), neg(y)) → minus_nat(y, x)
minus_int(neg(x), pos(y)) → neg(plus_nat(x, y))
minus_int(pos(x), neg(y)) → pos(plus_nat(x, y))

The set Q consists of the following terms:

f91(x0)
cond(true, x0)
cond(false, x0)
lesseq_int(pos(0), pos(x0))
lesseq_int(pos(0), neg(0))
lesseq_int(neg(x0), pos(x1))
lesseq_int(neg(x0), neg(0))
lesseq_int(pos(x0), neg(s(x1)))
lesseq_int(neg(0), neg(s(x0)))
lesseq_int(pos(s(x0)), pos(0))
lesseq_int(pos(s(x0)), neg(x1))
lesseq_int(pos(s(x0)), pos(s(x1)))
lesseq_int(neg(s(x0)), neg(s(x1)))
plus_int(pos(x0), neg(x1))
plus_int(neg(x0), pos(x1))
plus_int(neg(x0), neg(x1))
plus_int(pos(x0), pos(x1))
plus_nat(0, x0)
plus_nat(s(x0), x1)
minus_nat(0, 0)
minus_nat(0, s(x0))
minus_nat(s(x0), 0)
minus_nat(s(x0), s(x1))
minus_int(pos(x0), pos(x1))
minus_int(neg(x0), neg(x1))
minus_int(neg(x0), pos(x1))
minus_int(pos(x0), neg(x1))


Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem:
Q DP problem:
The TRS P consists of the following rules:

F91(n) → COND(lesseq_int(n, pos(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))), n)
F91(n) → LESSEQ_INT(n, pos(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(0))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))
COND(true, n) → F91(f91(plus_int(pos(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))), n)))
COND(true, n) → F91(plus_int(pos(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))), n))
COND(true, n) → PLUS_INT(pos(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))), n)
COND(false, n) → MINUS_INT(n, pos(s(s(s(s(s(s(s(s(s(s(0))))))))))))
LESSEQ_INT(pos(s(x)), pos(s(y))) → LESSEQ_INT(pos(x), pos(y))
LESSEQ_INT(neg(s(x)), neg(s(y))) → LESSEQ_INT(neg(x), neg(y))
PLUS_INT(pos(x), neg(y)) → MINUS_NAT(x, y)
PLUS_INT(neg(x), pos(y)) → MINUS_NAT(y, x)
PLUS_INT(neg(x), neg(y)) → PLUS_NAT(x, y)
PLUS_INT(pos(x), pos(y)) → PLUS_NAT(x, y)
PLUS_NAT(s(x), y) → PLUS_NAT(x, y)
MINUS_NAT(s(x), s(y)) → MINUS_NAT(x, y)
MINUS_INT(pos(x), pos(y)) → MINUS_NAT(x, y)
MINUS_INT(neg(x), neg(y)) → MINUS_NAT(y, x)
MINUS_INT(neg(x), pos(y)) → PLUS_NAT(x, y)
MINUS_INT(pos(x), neg(y)) → PLUS_NAT(x, y)

The TRS R consists of the following rules:

f91(n) → cond(lesseq_int(n, pos(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))), n)
cond(true, n) → f91(f91(plus_int(pos(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))), n)))
cond(false, n) → minus_int(n, pos(s(s(s(s(s(s(s(s(s(s(0))))))))))))
lesseq_int(pos(0), pos(y)) → true
lesseq_int(pos(0), neg(0)) → true
lesseq_int(neg(x), pos(y)) → true
lesseq_int(neg(x), neg(0)) → true
lesseq_int(pos(x), neg(s(y))) → false
lesseq_int(neg(0), neg(s(y))) → false
lesseq_int(pos(s(x)), pos(0)) → false
lesseq_int(pos(s(x)), neg(y)) → false
lesseq_int(pos(s(x)), pos(s(y))) → lesseq_int(pos(x), pos(y))
lesseq_int(neg(s(x)), neg(s(y))) → lesseq_int(neg(x), neg(y))
plus_int(pos(x), neg(y)) → minus_nat(x, y)
plus_int(neg(x), pos(y)) → minus_nat(y, x)
plus_int(neg(x), neg(y)) → neg(plus_nat(x, y))
plus_int(pos(x), pos(y)) → pos(plus_nat(x, y))
plus_nat(0, x) → x
plus_nat(s(x), y) → s(plus_nat(x, y))
minus_nat(0, 0) → pos(0)
minus_nat(0, s(y)) → neg(s(y))
minus_nat(s(x), 0) → pos(s(x))
minus_nat(s(x), s(y)) → minus_nat(x, y)
minus_int(pos(x), pos(y)) → minus_nat(x, y)
minus_int(neg(x), neg(y)) → minus_nat(y, x)
minus_int(neg(x), pos(y)) → neg(plus_nat(x, y))
minus_int(pos(x), neg(y)) → pos(plus_nat(x, y))

The set Q consists of the following terms:

f91(x0)
cond(true, x0)
cond(false, x0)
lesseq_int(pos(0), pos(x0))
lesseq_int(pos(0), neg(0))
lesseq_int(neg(x0), pos(x1))
lesseq_int(neg(x0), neg(0))
lesseq_int(pos(x0), neg(s(x1)))
lesseq_int(neg(0), neg(s(x0)))
lesseq_int(pos(s(x0)), pos(0))
lesseq_int(pos(s(x0)), neg(x1))
lesseq_int(pos(s(x0)), pos(s(x1)))
lesseq_int(neg(s(x0)), neg(s(x1)))
plus_int(pos(x0), neg(x1))
plus_int(neg(x0), pos(x1))
plus_int(neg(x0), neg(x1))
plus_int(pos(x0), pos(x1))
plus_nat(0, x0)
plus_nat(s(x0), x1)
minus_nat(0, 0)
minus_nat(0, s(x0))
minus_nat(s(x0), 0)
minus_nat(s(x0), s(x1))
minus_int(pos(x0), pos(x1))
minus_int(neg(x0), neg(x1))
minus_int(neg(x0), pos(x1))
minus_int(pos(x0), neg(x1))

We have to consider all minimal (P,Q,R)-chains.

↳ ITRS
  ↳ ITRStoQTRSProof
    ↳ QTRS
      ↳ DependencyPairsProof
        ↳ QDP
          ↳ DependencyGraphProof

Q DP problem:
The TRS P consists of the following rules:

F91(n) → COND(lesseq_int(n, pos(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))), n)
F91(n) → LESSEQ_INT(n, pos(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(0))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))
COND(true, n) → F91(f91(plus_int(pos(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))), n)))
COND(true, n) → F91(plus_int(pos(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))), n))
COND(true, n) → PLUS_INT(pos(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))), n)
COND(false, n) → MINUS_INT(n, pos(s(s(s(s(s(s(s(s(s(s(0))))))))))))
LESSEQ_INT(pos(s(x)), pos(s(y))) → LESSEQ_INT(pos(x), pos(y))
LESSEQ_INT(neg(s(x)), neg(s(y))) → LESSEQ_INT(neg(x), neg(y))
PLUS_INT(pos(x), neg(y)) → MINUS_NAT(x, y)
PLUS_INT(neg(x), pos(y)) → MINUS_NAT(y, x)
PLUS_INT(neg(x), neg(y)) → PLUS_NAT(x, y)
PLUS_INT(pos(x), pos(y)) → PLUS_NAT(x, y)
PLUS_NAT(s(x), y) → PLUS_NAT(x, y)
MINUS_NAT(s(x), s(y)) → MINUS_NAT(x, y)
MINUS_INT(pos(x), pos(y)) → MINUS_NAT(x, y)
MINUS_INT(neg(x), neg(y)) → MINUS_NAT(y, x)
MINUS_INT(neg(x), pos(y)) → PLUS_NAT(x, y)
MINUS_INT(pos(x), neg(y)) → PLUS_NAT(x, y)

The TRS R consists of the following rules:

f91(n) → cond(lesseq_int(n, pos(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))), n)
cond(true, n) → f91(f91(plus_int(pos(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))), n)))
cond(false, n) → minus_int(n, pos(s(s(s(s(s(s(s(s(s(s(0))))))))))))
lesseq_int(pos(0), pos(y)) → true
lesseq_int(pos(0), neg(0)) → true
lesseq_int(neg(x), pos(y)) → true
lesseq_int(neg(x), neg(0)) → true
lesseq_int(pos(x), neg(s(y))) → false
lesseq_int(neg(0), neg(s(y))) → false
lesseq_int(pos(s(x)), pos(0)) → false
lesseq_int(pos(s(x)), neg(y)) → false
lesseq_int(pos(s(x)), pos(s(y))) → lesseq_int(pos(x), pos(y))
lesseq_int(neg(s(x)), neg(s(y))) → lesseq_int(neg(x), neg(y))
plus_int(pos(x), neg(y)) → minus_nat(x, y)
plus_int(neg(x), pos(y)) → minus_nat(y, x)
plus_int(neg(x), neg(y)) → neg(plus_nat(x, y))
plus_int(pos(x), pos(y)) → pos(plus_nat(x, y))
plus_nat(0, x) → x
plus_nat(s(x), y) → s(plus_nat(x, y))
minus_nat(0, 0) → pos(0)
minus_nat(0, s(y)) → neg(s(y))
minus_nat(s(x), 0) → pos(s(x))
minus_nat(s(x), s(y)) → minus_nat(x, y)
minus_int(pos(x), pos(y)) → minus_nat(x, y)
minus_int(neg(x), neg(y)) → minus_nat(y, x)
minus_int(neg(x), pos(y)) → neg(plus_nat(x, y))
minus_int(pos(x), neg(y)) → pos(plus_nat(x, y))

The set Q consists of the following terms:

f91(x0)
cond(true, x0)
cond(false, x0)
lesseq_int(pos(0), pos(x0))
lesseq_int(pos(0), neg(0))
lesseq_int(neg(x0), pos(x1))
lesseq_int(neg(x0), neg(0))
lesseq_int(pos(x0), neg(s(x1)))
lesseq_int(neg(0), neg(s(x0)))
lesseq_int(pos(s(x0)), pos(0))
lesseq_int(pos(s(x0)), neg(x1))
lesseq_int(pos(s(x0)), pos(s(x1)))
lesseq_int(neg(s(x0)), neg(s(x1)))
plus_int(pos(x0), neg(x1))
plus_int(neg(x0), pos(x1))
plus_int(neg(x0), neg(x1))
plus_int(pos(x0), pos(x1))
plus_nat(0, x0)
plus_nat(s(x0), x1)
minus_nat(0, 0)
minus_nat(0, s(x0))
minus_nat(s(x0), 0)
minus_nat(s(x0), s(x1))
minus_int(pos(x0), pos(x1))
minus_int(neg(x0), neg(x1))
minus_int(neg(x0), pos(x1))
minus_int(pos(x0), neg(x1))

We have to consider all minimal (P,Q,R)-chains.
The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 5 SCCs with 11 less nodes.

↳ ITRS
  ↳ ITRStoQTRSProof
    ↳ QTRS
      ↳ DependencyPairsProof
        ↳ QDP
          ↳ DependencyGraphProof
            ↳ AND
              ↳ QDP
                ↳ UsableRulesProof
              ↳ QDP
              ↳ QDP
              ↳ QDP
              ↳ QDP

Q DP problem:
The TRS P consists of the following rules:

MINUS_NAT(s(x), s(y)) → MINUS_NAT(x, y)

The TRS R consists of the following rules:

f91(n) → cond(lesseq_int(n, pos(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))), n)
cond(true, n) → f91(f91(plus_int(pos(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))), n)))
cond(false, n) → minus_int(n, pos(s(s(s(s(s(s(s(s(s(s(0))))))))))))
lesseq_int(pos(0), pos(y)) → true
lesseq_int(pos(0), neg(0)) → true
lesseq_int(neg(x), pos(y)) → true
lesseq_int(neg(x), neg(0)) → true
lesseq_int(pos(x), neg(s(y))) → false
lesseq_int(neg(0), neg(s(y))) → false
lesseq_int(pos(s(x)), pos(0)) → false
lesseq_int(pos(s(x)), neg(y)) → false
lesseq_int(pos(s(x)), pos(s(y))) → lesseq_int(pos(x), pos(y))
lesseq_int(neg(s(x)), neg(s(y))) → lesseq_int(neg(x), neg(y))
plus_int(pos(x), neg(y)) → minus_nat(x, y)
plus_int(neg(x), pos(y)) → minus_nat(y, x)
plus_int(neg(x), neg(y)) → neg(plus_nat(x, y))
plus_int(pos(x), pos(y)) → pos(plus_nat(x, y))
plus_nat(0, x) → x
plus_nat(s(x), y) → s(plus_nat(x, y))
minus_nat(0, 0) → pos(0)
minus_nat(0, s(y)) → neg(s(y))
minus_nat(s(x), 0) → pos(s(x))
minus_nat(s(x), s(y)) → minus_nat(x, y)
minus_int(pos(x), pos(y)) → minus_nat(x, y)
minus_int(neg(x), neg(y)) → minus_nat(y, x)
minus_int(neg(x), pos(y)) → neg(plus_nat(x, y))
minus_int(pos(x), neg(y)) → pos(plus_nat(x, y))

The set Q consists of the following terms:

f91(x0)
cond(true, x0)
cond(false, x0)
lesseq_int(pos(0), pos(x0))
lesseq_int(pos(0), neg(0))
lesseq_int(neg(x0), pos(x1))
lesseq_int(neg(x0), neg(0))
lesseq_int(pos(x0), neg(s(x1)))
lesseq_int(neg(0), neg(s(x0)))
lesseq_int(pos(s(x0)), pos(0))
lesseq_int(pos(s(x0)), neg(x1))
lesseq_int(pos(s(x0)), pos(s(x1)))
lesseq_int(neg(s(x0)), neg(s(x1)))
plus_int(pos(x0), neg(x1))
plus_int(neg(x0), pos(x1))
plus_int(neg(x0), neg(x1))
plus_int(pos(x0), pos(x1))
plus_nat(0, x0)
plus_nat(s(x0), x1)
minus_nat(0, 0)
minus_nat(0, s(x0))
minus_nat(s(x0), 0)
minus_nat(s(x0), s(x1))
minus_int(pos(x0), pos(x1))
minus_int(neg(x0), neg(x1))
minus_int(neg(x0), pos(x1))
minus_int(pos(x0), neg(x1))

We have to consider all minimal (P,Q,R)-chains.
As all Q-normal forms are R-normal forms we are in the innermost case. Hence, by the usable rules processor [LPAR04] we can delete all non-usable rules [FROCOS05] from R.

↳ ITRS
  ↳ ITRStoQTRSProof
    ↳ QTRS
      ↳ DependencyPairsProof
        ↳ QDP
          ↳ DependencyGraphProof
            ↳ AND
              ↳ QDP
                ↳ UsableRulesProof
                  ↳ QDP
                    ↳ QReductionProof
              ↳ QDP
              ↳ QDP
              ↳ QDP
              ↳ QDP

Q DP problem:
The TRS P consists of the following rules:

MINUS_NAT(s(x), s(y)) → MINUS_NAT(x, y)

R is empty.
The set Q consists of the following terms:

f91(x0)
cond(true, x0)
cond(false, x0)
lesseq_int(pos(0), pos(x0))
lesseq_int(pos(0), neg(0))
lesseq_int(neg(x0), pos(x1))
lesseq_int(neg(x0), neg(0))
lesseq_int(pos(x0), neg(s(x1)))
lesseq_int(neg(0), neg(s(x0)))
lesseq_int(pos(s(x0)), pos(0))
lesseq_int(pos(s(x0)), neg(x1))
lesseq_int(pos(s(x0)), pos(s(x1)))
lesseq_int(neg(s(x0)), neg(s(x1)))
plus_int(pos(x0), neg(x1))
plus_int(neg(x0), pos(x1))
plus_int(neg(x0), neg(x1))
plus_int(pos(x0), pos(x1))
plus_nat(0, x0)
plus_nat(s(x0), x1)
minus_nat(0, 0)
minus_nat(0, s(x0))
minus_nat(s(x0), 0)
minus_nat(s(x0), s(x1))
minus_int(pos(x0), pos(x1))
minus_int(neg(x0), neg(x1))
minus_int(neg(x0), pos(x1))
minus_int(pos(x0), neg(x1))

We have to consider all minimal (P,Q,R)-chains.
We deleted the following terms from Q as each root-symbol of these terms does neither occur in P nor in R.[THIEMANN].

f91(x0)
cond(true, x0)
cond(false, x0)
lesseq_int(pos(0), pos(x0))
lesseq_int(pos(0), neg(0))
lesseq_int(neg(x0), pos(x1))
lesseq_int(neg(x0), neg(0))
lesseq_int(pos(x0), neg(s(x1)))
lesseq_int(neg(0), neg(s(x0)))
lesseq_int(pos(s(x0)), pos(0))
lesseq_int(pos(s(x0)), neg(x1))
lesseq_int(pos(s(x0)), pos(s(x1)))
lesseq_int(neg(s(x0)), neg(s(x1)))
plus_int(pos(x0), neg(x1))
plus_int(neg(x0), pos(x1))
plus_int(neg(x0), neg(x1))
plus_int(pos(x0), pos(x1))
plus_nat(0, x0)
plus_nat(s(x0), x1)
minus_nat(0, 0)
minus_nat(0, s(x0))
minus_nat(s(x0), 0)
minus_nat(s(x0), s(x1))
minus_int(pos(x0), pos(x1))
minus_int(neg(x0), neg(x1))
minus_int(neg(x0), pos(x1))
minus_int(pos(x0), neg(x1))



↳ ITRS
  ↳ ITRStoQTRSProof
    ↳ QTRS
      ↳ DependencyPairsProof
        ↳ QDP
          ↳ DependencyGraphProof
            ↳ AND
              ↳ QDP
                ↳ UsableRulesProof
                  ↳ QDP
                    ↳ QReductionProof
                      ↳ QDP
                        ↳ QDPSizeChangeProof
              ↳ QDP
              ↳ QDP
              ↳ QDP
              ↳ QDP

Q DP problem:
The TRS P consists of the following rules:

MINUS_NAT(s(x), s(y)) → MINUS_NAT(x, y)

R is empty.
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem.

From the DPs we obtained the following set of size-change graphs: 



↳ ITRS
  ↳ ITRStoQTRSProof
    ↳ QTRS
      ↳ DependencyPairsProof
        ↳ QDP
          ↳ DependencyGraphProof
            ↳ AND
              ↳ QDP
              ↳ QDP
                ↳ UsableRulesProof
              ↳ QDP
              ↳ QDP
              ↳ QDP

Q DP problem:
The TRS P consists of the following rules:

PLUS_NAT(s(x), y) → PLUS_NAT(x, y)

The TRS R consists of the following rules:

f91(n) → cond(lesseq_int(n, pos(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))), n)
cond(true, n) → f91(f91(plus_int(pos(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))), n)))
cond(false, n) → minus_int(n, pos(s(s(s(s(s(s(s(s(s(s(0))))))))))))
lesseq_int(pos(0), pos(y)) → true
lesseq_int(pos(0), neg(0)) → true
lesseq_int(neg(x), pos(y)) → true
lesseq_int(neg(x), neg(0)) → true
lesseq_int(pos(x), neg(s(y))) → false
lesseq_int(neg(0), neg(s(y))) → false
lesseq_int(pos(s(x)), pos(0)) → false
lesseq_int(pos(s(x)), neg(y)) → false
lesseq_int(pos(s(x)), pos(s(y))) → lesseq_int(pos(x), pos(y))
lesseq_int(neg(s(x)), neg(s(y))) → lesseq_int(neg(x), neg(y))
plus_int(pos(x), neg(y)) → minus_nat(x, y)
plus_int(neg(x), pos(y)) → minus_nat(y, x)
plus_int(neg(x), neg(y)) → neg(plus_nat(x, y))
plus_int(pos(x), pos(y)) → pos(plus_nat(x, y))
plus_nat(0, x) → x
plus_nat(s(x), y) → s(plus_nat(x, y))
minus_nat(0, 0) → pos(0)
minus_nat(0, s(y)) → neg(s(y))
minus_nat(s(x), 0) → pos(s(x))
minus_nat(s(x), s(y)) → minus_nat(x, y)
minus_int(pos(x), pos(y)) → minus_nat(x, y)
minus_int(neg(x), neg(y)) → minus_nat(y, x)
minus_int(neg(x), pos(y)) → neg(plus_nat(x, y))
minus_int(pos(x), neg(y)) → pos(plus_nat(x, y))

The set Q consists of the following terms:

f91(x0)
cond(true, x0)
cond(false, x0)
lesseq_int(pos(0), pos(x0))
lesseq_int(pos(0), neg(0))
lesseq_int(neg(x0), pos(x1))
lesseq_int(neg(x0), neg(0))
lesseq_int(pos(x0), neg(s(x1)))
lesseq_int(neg(0), neg(s(x0)))
lesseq_int(pos(s(x0)), pos(0))
lesseq_int(pos(s(x0)), neg(x1))
lesseq_int(pos(s(x0)), pos(s(x1)))
lesseq_int(neg(s(x0)), neg(s(x1)))
plus_int(pos(x0), neg(x1))
plus_int(neg(x0), pos(x1))
plus_int(neg(x0), neg(x1))
plus_int(pos(x0), pos(x1))
plus_nat(0, x0)
plus_nat(s(x0), x1)
minus_nat(0, 0)
minus_nat(0, s(x0))
minus_nat(s(x0), 0)
minus_nat(s(x0), s(x1))
minus_int(pos(x0), pos(x1))
minus_int(neg(x0), neg(x1))
minus_int(neg(x0), pos(x1))
minus_int(pos(x0), neg(x1))

We have to consider all minimal (P,Q,R)-chains.
As all Q-normal forms are R-normal forms we are in the innermost case. Hence, by the usable rules processor [LPAR04] we can delete all non-usable rules [FROCOS05] from R.

↳ ITRS
  ↳ ITRStoQTRSProof
    ↳ QTRS
      ↳ DependencyPairsProof
        ↳ QDP
          ↳ DependencyGraphProof
            ↳ AND
              ↳ QDP
              ↳ QDP
                ↳ UsableRulesProof
                  ↳ QDP
                    ↳ QReductionProof
              ↳ QDP
              ↳ QDP
              ↳ QDP

Q DP problem:
The TRS P consists of the following rules:

PLUS_NAT(s(x), y) → PLUS_NAT(x, y)

R is empty.
The set Q consists of the following terms:

f91(x0)
cond(true, x0)
cond(false, x0)
lesseq_int(pos(0), pos(x0))
lesseq_int(pos(0), neg(0))
lesseq_int(neg(x0), pos(x1))
lesseq_int(neg(x0), neg(0))
lesseq_int(pos(x0), neg(s(x1)))
lesseq_int(neg(0), neg(s(x0)))
lesseq_int(pos(s(x0)), pos(0))
lesseq_int(pos(s(x0)), neg(x1))
lesseq_int(pos(s(x0)), pos(s(x1)))
lesseq_int(neg(s(x0)), neg(s(x1)))
plus_int(pos(x0), neg(x1))
plus_int(neg(x0), pos(x1))
plus_int(neg(x0), neg(x1))
plus_int(pos(x0), pos(x1))
plus_nat(0, x0)
plus_nat(s(x0), x1)
minus_nat(0, 0)
minus_nat(0, s(x0))
minus_nat(s(x0), 0)
minus_nat(s(x0), s(x1))
minus_int(pos(x0), pos(x1))
minus_int(neg(x0), neg(x1))
minus_int(neg(x0), pos(x1))
minus_int(pos(x0), neg(x1))

We have to consider all minimal (P,Q,R)-chains.
We deleted the following terms from Q as each root-symbol of these terms does neither occur in P nor in R.[THIEMANN].

f91(x0)
cond(true, x0)
cond(false, x0)
lesseq_int(pos(0), pos(x0))
lesseq_int(pos(0), neg(0))
lesseq_int(neg(x0), pos(x1))
lesseq_int(neg(x0), neg(0))
lesseq_int(pos(x0), neg(s(x1)))
lesseq_int(neg(0), neg(s(x0)))
lesseq_int(pos(s(x0)), pos(0))
lesseq_int(pos(s(x0)), neg(x1))
lesseq_int(pos(s(x0)), pos(s(x1)))
lesseq_int(neg(s(x0)), neg(s(x1)))
plus_int(pos(x0), neg(x1))
plus_int(neg(x0), pos(x1))
plus_int(neg(x0), neg(x1))
plus_int(pos(x0), pos(x1))
plus_nat(0, x0)
plus_nat(s(x0), x1)
minus_nat(0, 0)
minus_nat(0, s(x0))
minus_nat(s(x0), 0)
minus_nat(s(x0), s(x1))
minus_int(pos(x0), pos(x1))
minus_int(neg(x0), neg(x1))
minus_int(neg(x0), pos(x1))
minus_int(pos(x0), neg(x1))



↳ ITRS
  ↳ ITRStoQTRSProof
    ↳ QTRS
      ↳ DependencyPairsProof
        ↳ QDP
          ↳ DependencyGraphProof
            ↳ AND
              ↳ QDP
              ↳ QDP
                ↳ UsableRulesProof
                  ↳ QDP
                    ↳ QReductionProof
                      ↳ QDP
                        ↳ QDPSizeChangeProof
              ↳ QDP
              ↳ QDP
              ↳ QDP

Q DP problem:
The TRS P consists of the following rules:

PLUS_NAT(s(x), y) → PLUS_NAT(x, y)

R is empty.
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem.

From the DPs we obtained the following set of size-change graphs: 



↳ ITRS
  ↳ ITRStoQTRSProof
    ↳ QTRS
      ↳ DependencyPairsProof
        ↳ QDP
          ↳ DependencyGraphProof
            ↳ AND
              ↳ QDP
              ↳ QDP
              ↳ QDP
                ↳ UsableRulesProof
              ↳ QDP
              ↳ QDP

Q DP problem:
The TRS P consists of the following rules:

LESSEQ_INT(neg(s(x)), neg(s(y))) → LESSEQ_INT(neg(x), neg(y))

The TRS R consists of the following rules:

f91(n) → cond(lesseq_int(n, pos(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))), n)
cond(true, n) → f91(f91(plus_int(pos(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))), n)))
cond(false, n) → minus_int(n, pos(s(s(s(s(s(s(s(s(s(s(0))))))))))))
lesseq_int(pos(0), pos(y)) → true
lesseq_int(pos(0), neg(0)) → true
lesseq_int(neg(x), pos(y)) → true
lesseq_int(neg(x), neg(0)) → true
lesseq_int(pos(x), neg(s(y))) → false
lesseq_int(neg(0), neg(s(y))) → false
lesseq_int(pos(s(x)), pos(0)) → false
lesseq_int(pos(s(x)), neg(y)) → false
lesseq_int(pos(s(x)), pos(s(y))) → lesseq_int(pos(x), pos(y))
lesseq_int(neg(s(x)), neg(s(y))) → lesseq_int(neg(x), neg(y))
plus_int(pos(x), neg(y)) → minus_nat(x, y)
plus_int(neg(x), pos(y)) → minus_nat(y, x)
plus_int(neg(x), neg(y)) → neg(plus_nat(x, y))
plus_int(pos(x), pos(y)) → pos(plus_nat(x, y))
plus_nat(0, x) → x
plus_nat(s(x), y) → s(plus_nat(x, y))
minus_nat(0, 0) → pos(0)
minus_nat(0, s(y)) → neg(s(y))
minus_nat(s(x), 0) → pos(s(x))
minus_nat(s(x), s(y)) → minus_nat(x, y)
minus_int(pos(x), pos(y)) → minus_nat(x, y)
minus_int(neg(x), neg(y)) → minus_nat(y, x)
minus_int(neg(x), pos(y)) → neg(plus_nat(x, y))
minus_int(pos(x), neg(y)) → pos(plus_nat(x, y))

The set Q consists of the following terms:

f91(x0)
cond(true, x0)
cond(false, x0)
lesseq_int(pos(0), pos(x0))
lesseq_int(pos(0), neg(0))
lesseq_int(neg(x0), pos(x1))
lesseq_int(neg(x0), neg(0))
lesseq_int(pos(x0), neg(s(x1)))
lesseq_int(neg(0), neg(s(x0)))
lesseq_int(pos(s(x0)), pos(0))
lesseq_int(pos(s(x0)), neg(x1))
lesseq_int(pos(s(x0)), pos(s(x1)))
lesseq_int(neg(s(x0)), neg(s(x1)))
plus_int(pos(x0), neg(x1))
plus_int(neg(x0), pos(x1))
plus_int(neg(x0), neg(x1))
plus_int(pos(x0), pos(x1))
plus_nat(0, x0)
plus_nat(s(x0), x1)
minus_nat(0, 0)
minus_nat(0, s(x0))
minus_nat(s(x0), 0)
minus_nat(s(x0), s(x1))
minus_int(pos(x0), pos(x1))
minus_int(neg(x0), neg(x1))
minus_int(neg(x0), pos(x1))
minus_int(pos(x0), neg(x1))

We have to consider all minimal (P,Q,R)-chains.
As all Q-normal forms are R-normal forms we are in the innermost case. Hence, by the usable rules processor [LPAR04] we can delete all non-usable rules [FROCOS05] from R.

↳ ITRS
  ↳ ITRStoQTRSProof
    ↳ QTRS
      ↳ DependencyPairsProof
        ↳ QDP
          ↳ DependencyGraphProof
            ↳ AND
              ↳ QDP
              ↳ QDP
              ↳ QDP
                ↳ UsableRulesProof
                  ↳ QDP
                    ↳ QReductionProof
              ↳ QDP
              ↳ QDP

Q DP problem:
The TRS P consists of the following rules:

LESSEQ_INT(neg(s(x)), neg(s(y))) → LESSEQ_INT(neg(x), neg(y))

R is empty.
The set Q consists of the following terms:

f91(x0)
cond(true, x0)
cond(false, x0)
lesseq_int(pos(0), pos(x0))
lesseq_int(pos(0), neg(0))
lesseq_int(neg(x0), pos(x1))
lesseq_int(neg(x0), neg(0))
lesseq_int(pos(x0), neg(s(x1)))
lesseq_int(neg(0), neg(s(x0)))
lesseq_int(pos(s(x0)), pos(0))
lesseq_int(pos(s(x0)), neg(x1))
lesseq_int(pos(s(x0)), pos(s(x1)))
lesseq_int(neg(s(x0)), neg(s(x1)))
plus_int(pos(x0), neg(x1))
plus_int(neg(x0), pos(x1))
plus_int(neg(x0), neg(x1))
plus_int(pos(x0), pos(x1))
plus_nat(0, x0)
plus_nat(s(x0), x1)
minus_nat(0, 0)
minus_nat(0, s(x0))
minus_nat(s(x0), 0)
minus_nat(s(x0), s(x1))
minus_int(pos(x0), pos(x1))
minus_int(neg(x0), neg(x1))
minus_int(neg(x0), pos(x1))
minus_int(pos(x0), neg(x1))

We have to consider all minimal (P,Q,R)-chains.
We deleted the following terms from Q as each root-symbol of these terms does neither occur in P nor in R.[THIEMANN].

f91(x0)
cond(true, x0)
cond(false, x0)
lesseq_int(pos(0), pos(x0))
lesseq_int(pos(0), neg(0))
lesseq_int(neg(x0), pos(x1))
lesseq_int(neg(x0), neg(0))
lesseq_int(pos(x0), neg(s(x1)))
lesseq_int(neg(0), neg(s(x0)))
lesseq_int(pos(s(x0)), pos(0))
lesseq_int(pos(s(x0)), neg(x1))
lesseq_int(pos(s(x0)), pos(s(x1)))
lesseq_int(neg(s(x0)), neg(s(x1)))
plus_int(pos(x0), neg(x1))
plus_int(neg(x0), pos(x1))
plus_int(neg(x0), neg(x1))
plus_int(pos(x0), pos(x1))
plus_nat(0, x0)
plus_nat(s(x0), x1)
minus_nat(0, 0)
minus_nat(0, s(x0))
minus_nat(s(x0), 0)
minus_nat(s(x0), s(x1))
minus_int(pos(x0), pos(x1))
minus_int(neg(x0), neg(x1))
minus_int(neg(x0), pos(x1))
minus_int(pos(x0), neg(x1))



↳ ITRS
  ↳ ITRStoQTRSProof
    ↳ QTRS
      ↳ DependencyPairsProof
        ↳ QDP
          ↳ DependencyGraphProof
            ↳ AND
              ↳ QDP
              ↳ QDP
              ↳ QDP
                ↳ UsableRulesProof
                  ↳ QDP
                    ↳ QReductionProof
                      ↳ QDP
                        ↳ UsableRulesReductionPairsProof
              ↳ QDP
              ↳ QDP

Q DP problem:
The TRS P consists of the following rules:

LESSEQ_INT(neg(s(x)), neg(s(y))) → LESSEQ_INT(neg(x), neg(y))

R is empty.
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
By using the usable rules with reduction pair processor [LPAR04] with a polynomial ordering [POLO], all dependency pairs and the corresponding usable rules [FROCOS05] can be oriented non-strictly. All non-usable rules are removed, and those dependency pairs and usable rules that have been oriented strictly or contain non-usable symbols in their left-hand side are removed as well.

The following dependency pairs can be deleted:

LESSEQ_INT(neg(s(x)), neg(s(y))) → LESSEQ_INT(neg(x), neg(y))
No rules are removed from R.

Used ordering: POLO with Polynomial interpretation [POLO]:

POL(LESSEQ_INT(x1, x2)) = 2·x1 + x2   
POL(neg(x1)) = x1   
POL(s(x1)) = 2·x1   



↳ ITRS
  ↳ ITRStoQTRSProof
    ↳ QTRS
      ↳ DependencyPairsProof
        ↳ QDP
          ↳ DependencyGraphProof
            ↳ AND
              ↳ QDP
              ↳ QDP
              ↳ QDP
                ↳ UsableRulesProof
                  ↳ QDP
                    ↳ QReductionProof
                      ↳ QDP
                        ↳ UsableRulesReductionPairsProof
                          ↳ QDP
                            ↳ PisEmptyProof
              ↳ QDP
              ↳ QDP

Q DP problem:
P is empty.
R is empty.
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
The TRS P is empty. Hence, there is no (P,Q,R) chain.

↳ ITRS
  ↳ ITRStoQTRSProof
    ↳ QTRS
      ↳ DependencyPairsProof
        ↳ QDP
          ↳ DependencyGraphProof
            ↳ AND
              ↳ QDP
              ↳ QDP
              ↳ QDP
              ↳ QDP
                ↳ UsableRulesProof
              ↳ QDP

Q DP problem:
The TRS P consists of the following rules:

LESSEQ_INT(pos(s(x)), pos(s(y))) → LESSEQ_INT(pos(x), pos(y))

The TRS R consists of the following rules:

f91(n) → cond(lesseq_int(n, pos(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))), n)
cond(true, n) → f91(f91(plus_int(pos(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))), n)))
cond(false, n) → minus_int(n, pos(s(s(s(s(s(s(s(s(s(s(0))))))))))))
lesseq_int(pos(0), pos(y)) → true
lesseq_int(pos(0), neg(0)) → true
lesseq_int(neg(x), pos(y)) → true
lesseq_int(neg(x), neg(0)) → true
lesseq_int(pos(x), neg(s(y))) → false
lesseq_int(neg(0), neg(s(y))) → false
lesseq_int(pos(s(x)), pos(0)) → false
lesseq_int(pos(s(x)), neg(y)) → false
lesseq_int(pos(s(x)), pos(s(y))) → lesseq_int(pos(x), pos(y))
lesseq_int(neg(s(x)), neg(s(y))) → lesseq_int(neg(x), neg(y))
plus_int(pos(x), neg(y)) → minus_nat(x, y)
plus_int(neg(x), pos(y)) → minus_nat(y, x)
plus_int(neg(x), neg(y)) → neg(plus_nat(x, y))
plus_int(pos(x), pos(y)) → pos(plus_nat(x, y))
plus_nat(0, x) → x
plus_nat(s(x), y) → s(plus_nat(x, y))
minus_nat(0, 0) → pos(0)
minus_nat(0, s(y)) → neg(s(y))
minus_nat(s(x), 0) → pos(s(x))
minus_nat(s(x), s(y)) → minus_nat(x, y)
minus_int(pos(x), pos(y)) → minus_nat(x, y)
minus_int(neg(x), neg(y)) → minus_nat(y, x)
minus_int(neg(x), pos(y)) → neg(plus_nat(x, y))
minus_int(pos(x), neg(y)) → pos(plus_nat(x, y))

The set Q consists of the following terms:

f91(x0)
cond(true, x0)
cond(false, x0)
lesseq_int(pos(0), pos(x0))
lesseq_int(pos(0), neg(0))
lesseq_int(neg(x0), pos(x1))
lesseq_int(neg(x0), neg(0))
lesseq_int(pos(x0), neg(s(x1)))
lesseq_int(neg(0), neg(s(x0)))
lesseq_int(pos(s(x0)), pos(0))
lesseq_int(pos(s(x0)), neg(x1))
lesseq_int(pos(s(x0)), pos(s(x1)))
lesseq_int(neg(s(x0)), neg(s(x1)))
plus_int(pos(x0), neg(x1))
plus_int(neg(x0), pos(x1))
plus_int(neg(x0), neg(x1))
plus_int(pos(x0), pos(x1))
plus_nat(0, x0)
plus_nat(s(x0), x1)
minus_nat(0, 0)
minus_nat(0, s(x0))
minus_nat(s(x0), 0)
minus_nat(s(x0), s(x1))
minus_int(pos(x0), pos(x1))
minus_int(neg(x0), neg(x1))
minus_int(neg(x0), pos(x1))
minus_int(pos(x0), neg(x1))

We have to consider all minimal (P,Q,R)-chains.
As all Q-normal forms are R-normal forms we are in the innermost case. Hence, by the usable rules processor [LPAR04] we can delete all non-usable rules [FROCOS05] from R.

↳ ITRS
  ↳ ITRStoQTRSProof
    ↳ QTRS
      ↳ DependencyPairsProof
        ↳ QDP
          ↳ DependencyGraphProof
            ↳ AND
              ↳ QDP
              ↳ QDP
              ↳ QDP
              ↳ QDP
                ↳ UsableRulesProof
                  ↳ QDP
                    ↳ QReductionProof
              ↳ QDP

Q DP problem:
The TRS P consists of the following rules:

LESSEQ_INT(pos(s(x)), pos(s(y))) → LESSEQ_INT(pos(x), pos(y))

R is empty.
The set Q consists of the following terms:

f91(x0)
cond(true, x0)
cond(false, x0)
lesseq_int(pos(0), pos(x0))
lesseq_int(pos(0), neg(0))
lesseq_int(neg(x0), pos(x1))
lesseq_int(neg(x0), neg(0))
lesseq_int(pos(x0), neg(s(x1)))
lesseq_int(neg(0), neg(s(x0)))
lesseq_int(pos(s(x0)), pos(0))
lesseq_int(pos(s(x0)), neg(x1))
lesseq_int(pos(s(x0)), pos(s(x1)))
lesseq_int(neg(s(x0)), neg(s(x1)))
plus_int(pos(x0), neg(x1))
plus_int(neg(x0), pos(x1))
plus_int(neg(x0), neg(x1))
plus_int(pos(x0), pos(x1))
plus_nat(0, x0)
plus_nat(s(x0), x1)
minus_nat(0, 0)
minus_nat(0, s(x0))
minus_nat(s(x0), 0)
minus_nat(s(x0), s(x1))
minus_int(pos(x0), pos(x1))
minus_int(neg(x0), neg(x1))
minus_int(neg(x0), pos(x1))
minus_int(pos(x0), neg(x1))

We have to consider all minimal (P,Q,R)-chains.
We deleted the following terms from Q as each root-symbol of these terms does neither occur in P nor in R.[THIEMANN].

f91(x0)
cond(true, x0)
cond(false, x0)
lesseq_int(pos(0), pos(x0))
lesseq_int(pos(0), neg(0))
lesseq_int(neg(x0), pos(x1))
lesseq_int(neg(x0), neg(0))
lesseq_int(pos(x0), neg(s(x1)))
lesseq_int(neg(0), neg(s(x0)))
lesseq_int(pos(s(x0)), pos(0))
lesseq_int(pos(s(x0)), neg(x1))
lesseq_int(pos(s(x0)), pos(s(x1)))
lesseq_int(neg(s(x0)), neg(s(x1)))
plus_int(pos(x0), neg(x1))
plus_int(neg(x0), pos(x1))
plus_int(neg(x0), neg(x1))
plus_int(pos(x0), pos(x1))
plus_nat(0, x0)
plus_nat(s(x0), x1)
minus_nat(0, 0)
minus_nat(0, s(x0))
minus_nat(s(x0), 0)
minus_nat(s(x0), s(x1))
minus_int(pos(x0), pos(x1))
minus_int(neg(x0), neg(x1))
minus_int(neg(x0), pos(x1))
minus_int(pos(x0), neg(x1))



↳ ITRS
  ↳ ITRStoQTRSProof
    ↳ QTRS
      ↳ DependencyPairsProof
        ↳ QDP
          ↳ DependencyGraphProof
            ↳ AND
              ↳ QDP
              ↳ QDP
              ↳ QDP
              ↳ QDP
                ↳ UsableRulesProof
                  ↳ QDP
                    ↳ QReductionProof
                      ↳ QDP
                        ↳ UsableRulesReductionPairsProof
              ↳ QDP

Q DP problem:
The TRS P consists of the following rules:

LESSEQ_INT(pos(s(x)), pos(s(y))) → LESSEQ_INT(pos(x), pos(y))

R is empty.
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
By using the usable rules with reduction pair processor [LPAR04] with a polynomial ordering [POLO], all dependency pairs and the corresponding usable rules [FROCOS05] can be oriented non-strictly. All non-usable rules are removed, and those dependency pairs and usable rules that have been oriented strictly or contain non-usable symbols in their left-hand side are removed as well.

The following dependency pairs can be deleted:

LESSEQ_INT(pos(s(x)), pos(s(y))) → LESSEQ_INT(pos(x), pos(y))
No rules are removed from R.

Used ordering: POLO with Polynomial interpretation [POLO]:

POL(LESSEQ_INT(x1, x2)) = 2·x1 + x2   
POL(pos(x1)) = x1   
POL(s(x1)) = 2·x1   



↳ ITRS
  ↳ ITRStoQTRSProof
    ↳ QTRS
      ↳ DependencyPairsProof
        ↳ QDP
          ↳ DependencyGraphProof
            ↳ AND
              ↳ QDP
              ↳ QDP
              ↳ QDP
              ↳ QDP
                ↳ UsableRulesProof
                  ↳ QDP
                    ↳ QReductionProof
                      ↳ QDP
                        ↳ UsableRulesReductionPairsProof
                          ↳ QDP
                            ↳ PisEmptyProof
              ↳ QDP

Q DP problem:
P is empty.
R is empty.
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
The TRS P is empty. Hence, there is no (P,Q,R) chain.

↳ ITRS
  ↳ ITRStoQTRSProof
    ↳ QTRS
      ↳ DependencyPairsProof
        ↳ QDP
          ↳ DependencyGraphProof
            ↳ AND
              ↳ QDP
              ↳ QDP
              ↳ QDP
              ↳ QDP
              ↳ QDP
                ↳ UsableRulesProof

Q DP problem:
The TRS P consists of the following rules:

COND(true, n) → F91(f91(plus_int(pos(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))), n)))
F91(n) → COND(lesseq_int(n, pos(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))), n)
COND(true, n) → F91(plus_int(pos(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))), n))

The TRS R consists of the following rules:

f91(n) → cond(lesseq_int(n, pos(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))), n)
cond(true, n) → f91(f91(plus_int(pos(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))), n)))
cond(false, n) → minus_int(n, pos(s(s(s(s(s(s(s(s(s(s(0))))))))))))
lesseq_int(pos(0), pos(y)) → true
lesseq_int(pos(0), neg(0)) → true
lesseq_int(neg(x), pos(y)) → true
lesseq_int(neg(x), neg(0)) → true
lesseq_int(pos(x), neg(s(y))) → false
lesseq_int(neg(0), neg(s(y))) → false
lesseq_int(pos(s(x)), pos(0)) → false
lesseq_int(pos(s(x)), neg(y)) → false
lesseq_int(pos(s(x)), pos(s(y))) → lesseq_int(pos(x), pos(y))
lesseq_int(neg(s(x)), neg(s(y))) → lesseq_int(neg(x), neg(y))
plus_int(pos(x), neg(y)) → minus_nat(x, y)
plus_int(neg(x), pos(y)) → minus_nat(y, x)
plus_int(neg(x), neg(y)) → neg(plus_nat(x, y))
plus_int(pos(x), pos(y)) → pos(plus_nat(x, y))
plus_nat(0, x) → x
plus_nat(s(x), y) → s(plus_nat(x, y))
minus_nat(0, 0) → pos(0)
minus_nat(0, s(y)) → neg(s(y))
minus_nat(s(x), 0) → pos(s(x))
minus_nat(s(x), s(y)) → minus_nat(x, y)
minus_int(pos(x), pos(y)) → minus_nat(x, y)
minus_int(neg(x), neg(y)) → minus_nat(y, x)
minus_int(neg(x), pos(y)) → neg(plus_nat(x, y))
minus_int(pos(x), neg(y)) → pos(plus_nat(x, y))

The set Q consists of the following terms:

f91(x0)
cond(true, x0)
cond(false, x0)
lesseq_int(pos(0), pos(x0))
lesseq_int(pos(0), neg(0))
lesseq_int(neg(x0), pos(x1))
lesseq_int(neg(x0), neg(0))
lesseq_int(pos(x0), neg(s(x1)))
lesseq_int(neg(0), neg(s(x0)))
lesseq_int(pos(s(x0)), pos(0))
lesseq_int(pos(s(x0)), neg(x1))
lesseq_int(pos(s(x0)), pos(s(x1)))
lesseq_int(neg(s(x0)), neg(s(x1)))
plus_int(pos(x0), neg(x1))
plus_int(neg(x0), pos(x1))
plus_int(neg(x0), neg(x1))
plus_int(pos(x0), pos(x1))
plus_nat(0, x0)
plus_nat(s(x0), x1)
minus_nat(0, 0)
minus_nat(0, s(x0))
minus_nat(s(x0), 0)
minus_nat(s(x0), s(x1))
minus_int(pos(x0), pos(x1))
minus_int(neg(x0), neg(x1))
minus_int(neg(x0), pos(x1))
minus_int(pos(x0), neg(x1))

We have to consider all minimal (P,Q,R)-chains.
As all Q-normal forms are R-normal forms we are in the innermost case. Hence, by the usable rules processor [LPAR04] we can delete all non-usable rules [FROCOS05] from R.

↳ ITRS
  ↳ ITRStoQTRSProof
    ↳ QTRS
      ↳ DependencyPairsProof
        ↳ QDP
          ↳ DependencyGraphProof
            ↳ AND
              ↳ QDP
              ↳ QDP
              ↳ QDP
              ↳ QDP
              ↳ QDP
                ↳ UsableRulesProof
                  ↳ QDP
                    ↳ Rewriting

Q DP problem:
The TRS P consists of the following rules:

COND(true, n) → F91(f91(plus_int(pos(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))), n)))
F91(n) → COND(lesseq_int(n, pos(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))), n)
COND(true, n) → F91(plus_int(pos(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))), n))

The TRS R consists of the following rules:

plus_int(pos(x), neg(y)) → minus_nat(x, y)
plus_int(pos(x), pos(y)) → pos(plus_nat(x, y))
plus_nat(0, x) → x
plus_nat(s(x), y) → s(plus_nat(x, y))
minus_nat(0, 0) → pos(0)
minus_nat(0, s(y)) → neg(s(y))
minus_nat(s(x), 0) → pos(s(x))
minus_nat(s(x), s(y)) → minus_nat(x, y)
cond(true, n) → f91(f91(plus_int(pos(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))), n)))
f91(n) → cond(lesseq_int(n, pos(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))), n)
lesseq_int(pos(0), pos(y)) → true
lesseq_int(neg(x), pos(y)) → true
lesseq_int(pos(s(x)), pos(s(y))) → lesseq_int(pos(x), pos(y))
cond(false, n) → minus_int(n, pos(s(s(s(s(s(s(s(s(s(s(0))))))))))))
minus_int(pos(x), pos(y)) → minus_nat(x, y)
minus_int(neg(x), pos(y)) → neg(plus_nat(x, y))
lesseq_int(pos(s(x)), pos(0)) → false

The set Q consists of the following terms:

f91(x0)
cond(true, x0)
cond(false, x0)
lesseq_int(pos(0), pos(x0))
lesseq_int(pos(0), neg(0))
lesseq_int(neg(x0), pos(x1))
lesseq_int(neg(x0), neg(0))
lesseq_int(pos(x0), neg(s(x1)))
lesseq_int(neg(0), neg(s(x0)))
lesseq_int(pos(s(x0)), pos(0))
lesseq_int(pos(s(x0)), neg(x1))
lesseq_int(pos(s(x0)), pos(s(x1)))
lesseq_int(neg(s(x0)), neg(s(x1)))
plus_int(pos(x0), neg(x1))
plus_int(neg(x0), pos(x1))
plus_int(neg(x0), neg(x1))
plus_int(pos(x0), pos(x1))
plus_nat(0, x0)
plus_nat(s(x0), x1)
minus_nat(0, 0)
minus_nat(0, s(x0))
minus_nat(s(x0), 0)
minus_nat(s(x0), s(x1))
minus_int(pos(x0), pos(x1))
minus_int(neg(x0), neg(x1))
minus_int(neg(x0), pos(x1))
minus_int(pos(x0), neg(x1))

We have to consider all minimal (P,Q,R)-chains.
By rewriting [LPAR04] the rule COND(true, n) → F91(f91(plus_int(pos(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))), n))) at position [0] we obtained the following new rules [LPAR04]:

COND(true, n) → F91(cond(lesseq_int(plus_int(pos(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))), n), pos(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))), plus_int(pos(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))), n)))



↳ ITRS
  ↳ ITRStoQTRSProof
    ↳ QTRS
      ↳ DependencyPairsProof
        ↳ QDP
          ↳ DependencyGraphProof
            ↳ AND
              ↳ QDP
              ↳ QDP
              ↳ QDP
              ↳ QDP
              ↳ QDP
                ↳ UsableRulesProof
                  ↳ QDP
                    ↳ Rewriting
                      ↳ QDP

Q DP problem:
The TRS P consists of the following rules:

F91(n) → COND(lesseq_int(n, pos(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))), n)
COND(true, n) → F91(plus_int(pos(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))), n))
COND(true, n) → F91(cond(lesseq_int(plus_int(pos(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))), n), pos(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))), plus_int(pos(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))), n)))

The TRS R consists of the following rules:

plus_int(pos(x), neg(y)) → minus_nat(x, y)
plus_int(pos(x), pos(y)) → pos(plus_nat(x, y))
plus_nat(0, x) → x
plus_nat(s(x), y) → s(plus_nat(x, y))
minus_nat(0, 0) → pos(0)
minus_nat(0, s(y)) → neg(s(y))
minus_nat(s(x), 0) → pos(s(x))
minus_nat(s(x), s(y)) → minus_nat(x, y)
cond(true, n) → f91(f91(plus_int(pos(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))), n)))
f91(n) → cond(lesseq_int(n, pos(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(s(0)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))), n)
lesseq_int(pos(0), pos(y)) → true
lesseq_int(neg(x), pos(y)) → true
lesseq_int(pos(s(x)), pos(s(y))) → lesseq_int(pos(x), pos(y))
cond(false, n) → minus_int(n, pos(s(s(s(s(s(s(s(s(s(s(0))))))))))))
minus_int(pos(x), pos(y)) → minus_nat(x, y)
minus_int(neg(x), pos(y)) → neg(plus_nat(x, y))
lesseq_int(pos(s(x)), pos(0)) → false

The set Q consists of the following terms:

f91(x0)
cond(true, x0)
cond(false, x0)
lesseq_int(pos(0), pos(x0))
lesseq_int(pos(0), neg(0))
lesseq_int(neg(x0), pos(x1))
lesseq_int(neg(x0), neg(0))
lesseq_int(pos(x0), neg(s(x1)))
lesseq_int(neg(0), neg(s(x0)))
lesseq_int(pos(s(x0)), pos(0))
lesseq_int(pos(s(x0)), neg(x1))
lesseq_int(pos(s(x0)), pos(s(x1)))
lesseq_int(neg(s(x0)), neg(s(x1)))
plus_int(pos(x0), neg(x1))
plus_int(neg(x0), pos(x1))
plus_int(neg(x0), neg(x1))
plus_int(pos(x0), pos(x1))
plus_nat(0, x0)
plus_nat(s(x0), x1)
minus_nat(0, 0)
minus_nat(0, s(x0))
minus_nat(s(x0), 0)
minus_nat(s(x0), s(x1))
minus_int(pos(x0), pos(x1))
minus_int(neg(x0), neg(x1))
minus_int(neg(x0), pos(x1))
minus_int(pos(x0), neg(x1))

We have to consider all minimal (P,Q,R)-chains.